How many total oximes are possible for ketone | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For $C_3H_6O$ (Acetone): $CH_3COCH_3$ gives $1$ oxime (no geometrical isomerism).For $C_4H_8O$ (Butanone): $CH_3COCH_2CH_3$ gives $2$ oximes (syn

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(D) For $C_3H_6O$ (Acetone): $CH_3COCH_3$ gives $1$ oxime (no geometrical isomerism).For $C_4H_8O$ (Butanone): $CH_3COCH_2CH_3$ gives $2$ oximes (syn and anti isomers).For $C_5H_{10}O$ (Pentan$-2-$one,Pentan$-3-$one,$3$-Methylbutan$-2-$one):$CH_3COCH_2CH_2CH_3$ gives $2$ oximes (syn and anti).$CH_3CH_2COCH_2CH_3$ gives $1$ oxime (no geometrical isomerism).$CH_3COCH(CH_3)_2$ gives $2$ oximes (syn and anti).Total oximes = $1 + 2 + 2 + 1 + 2 = 8$.

Column-$I$ (Reactants)	Column-$II$ (Major Product)
$A$. $HCHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$i$. $C_6H_5CHOHCH_3$
$B$. $C_6H_5CHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$ii$. $(CH_3)_3COH$
$C$. $CH_3COCH_3 \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$iii$. $CH_3CHOHCH_3$
$D$. $CH_3CHO \xrightarrow{(i) CH_3MgBr, (ii) H_2O}$	$iv$. $CH_3CH_2OH$

How many total oximes are possible for ketones having molecular formula $C_3H_6O$,$C_4H_8O$ and $C_5H_{10}O$?

Similar Questions

Which product is obtained when cyclopentanone reacts with hydroxylamine in an acidic medium?

The silver mirror test is used to detect which of the following?

Which of the following will give a yellow precipitate with $I_2/NaOH$?

The major product formed in the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module